Question

the radius of a semi circle garden is 28 m. hoe much more distance has one to cover for going from A to B on the circular path instead of going on diametrical path?​

Answer 1

Answer:

1) Ato B Distance =2r=2x28=56m

2) A to B πr=22/7 x 28. 88m

distance in excess=88-56=32m. Ans

Answer 2

it is very simple

fence=

2\pi \: r

2

22  \div 7 \times 28