the radius of a semi circle garden is 28 m. hoe much more distance has one to cover for going from A to B on the circular path instead of going on diametrical path?
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Answered by
13
Answer:
1) Ato B Distance =2r=2x28=56m
2) A to B πr=22/7 x 28. 88m
distance in excess=88-56=32m. Ans
Answered by
1
it is very simple
fence=
2\pi \: r
2
22 \div 7 \times 28
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