Question

The radius of a shell for h-atom is 4.716 angstrom. The value of n is

Answer 1

The radius of a shell for H atom is 4.761A°. Then the value ... Here is the answer to your question: Equating-. n^2= 4.761/0.529 = 9. or,n=3. Thanks,.

Answer 2

The correct answer is 3.

Given: Atom = Hydrogen atom.

Radius = 4.716 A.

To Find: Value of n.

Solution:

Radius of a shell = $\frac{0.529*n^{2} }{Z}$ A

Atomic number of hydrogen (Z)= 1

4.716 = $\frac{0.529*n^{2} }{1}$

$n^{2} =\frac{4.716}{0.529}$

$n^{2}=8.9$

$n^{2}$ ≈ 9

n = 3

Hence, the shell number is 3.

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