Question

The radius of a soap bubble is increased from 1/√π cm to 2/ √π cm. If the surface tension of water is 30 dynes / cm , the work done will be
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Answer 1

Answer:

hope it's use full

Explanation:

Work done in blowing a soap bubble W=2T(A

2

−A

1

)

So W=2T(4πr

2

2

−4πr

1

2

)=8πT(

π

2

2

−

π

1

)=720erg