The radius of a soap bubble is increased from cm to cm. The surface tension of water is 30 dynes per cm. If the work done required is α × 10–6 J then find the value of α.
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Answer:
W=8πT(r
2
2
−r
1
2
)=8πT[(
π
2
)
2
−(
π
1
)
2
]
∴W=8∗π∗30∗
π
3
=720 erg.
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