Question

The radius of a sphere be doubled then the percentage of increase in volume is?.Only for topper students​

Answer 1

Answer:

700% increase in volume

Step-by-step explanation:

original radius = r

new radius = 2r

original volume=

$4/3 \times π \times {r}^{2}$

new volume =

$\frac{4}{3} \times \pi \times {(2r)}^{2}$

new volume=

$\frac{4}{3} \times \pi \times 8 \times {r}^{2}$

increase in volume =

$\frac{4}{3} \times \pi \times {r}^{2} (8 - 1)$

increase in volume=

$7 \times \frac{4}{3} \times \pi \times {r}^{2}$

Percentage increase=

700%

Answer 2

Answer:

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