the radius of a sphere increased 25%. find % increase in surface area
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Answered by
2
SA of sphere = 4pr^2
if r=r
and r' = r+25% of r
r'=125r/100
new SA=4*p*(25r/4)^2
SA = 4*p*625r^2/16
inc=16/625
Answered by
8
here is your answer::
radius increased by 25%
means 5/4
that's mean old is 4 and new is 5
4π(4)^2 =old
4π(5)^2= new
64π=old
100π= new
change = 100π-64π=36π
% increase = 36π/64π ×100
=56.25%
hope u get your answer....
mark me brainliest
divergent07:
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