Physics, asked by ac944735, 5 months ago

The radius of a sphere is 12.4 0.1 cm.
i. Calculate the percentage error in radius.
ii. Calculate the percentage error in sur face area of the sphere (A = 4Ttr?).​

Answers

Answered by bushranaz5657
0

Answer:

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Answered by AditiHegde
3

Given:

The radius of a sphere is 12.4 0.1 cm.

To find:

i. Calculate the percentage error in radius.

ii. Calculate the percentage error in sur face area of the sphere (A = 4Ttr?).​

Solution:

From the given information, we have the data as follows.

The radius of a sphere is 12.4 ± 0.1 cm.

⇒ r = 12.4

Δr = 0.1

i. The percentage error in radius.

= Δr/r × 100%

= 0.1/12.4 × 100%

ii. The percentage error in surface area of the sphere

S = 4πr²

S ∝ r²

ΔS/S × 100% = 2 Δr/r × 100%

ΔS/S × 100% = 2 × 0.1/12.4 × 100%

Therefore, the percentage error in radius and surface area are 0.1/12.4 × 100% and 2 × 0.1/12.4 × 100%

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