The radius of a sphere is (20.0 +0.2) cm. The
percentage error in its surface area is
4%
3%
2%
1%
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Given : The radius of a sphere is (20.0 +0.2) cm
To find : The percentage error in its surface area
Solution:
Surface area of sphere A = 4πR²
ΔA/A = 2ΔR/R
=> 100 * ΔA/A = 100 * 2ΔR/R
=> Percentage error in Surface Area = 2 ( Percentage error in Radius)
=> Percentage error in Surface Area = 100 * 2 * 0.2/20
=> Percentage error in Surface Area = 2
The percentage error in its surface area is 2 %
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Calculate the percentage error in measurement.
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0
Answer:
Step-by-step explanation:
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