Question

The radius of a sphere is (5.3 +- 0.1) can. The % error in its volume is?

Answer 1

Radius of the sphere = (5.3 +- 0.1) = 5.2

Volume of the sphere = (4/3) × (22/7) × 5.2 = 21.790476

We will round it off to the nearest 1.
So, the rounded answer will be 22.

To find the % of error we will do the below process
(21.790476/22) = 0.990476%.

Hope it helps.
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