The radius of a sphere is 5.3+-0.1cm.calculate its surface area with error limits?
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volume is
V = 4/3 pi r^3
for r=5.3 we get that
V = 4/3 * 3.1416 * 5.3^3 =
623.6145 cm^3
for r= 5.3 - 0.1 = 5.2
V0 = 4/3 * 3.1416 * 5.2^3 = 588.9774 cm^3
and for r=
5.3 + 0.1 = 5.4
V1 = 4/3 *
3.1416 * 5.4^3 = 659.5837 cm^3
Then the percentage error for surface area
is
(V-V0)/V =
(623.6145-588.9774)/623.6145 * 100 = 5.5542 %
(V1-V)/V =
(659.5837-623.6145)/623.6145 * 100 = 5.7679 %
percentage
error in volume is in the interval [-5.5542%, 5.7679%]
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