Question

The radius of a sphere is doubled. Find the increase per cent in its surface area
​

Answer 1

Let initial radius = r

0

initial surface area = 4πr

0

2

final radius = 2r

0

final surface area = 4π(2r

0

)

2

=4.4πr

0

2

=16πr

0

2

increase in surface area = 16πr

0

2

−4πr

0

2

=12πr

0

2

percent increase in surface area =

4πr

0

2

12πr

0

2

×100=300%

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Answer 2

Answer:

50

explanation

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