Question

the radius of a sphere is expressed as (5.3+ _0.1) cm.find the percentage error in the volume of the sphere. solve in the answere

Answer 1

V = (4/3) × πR³

ΔV/V = 3 × Δr/r
= 3 × (0.1 / 5.3)
= 0.0566

ΔV/V × 100 = 0.0566 × 100 = 5.66

Percentage error in volume is 5.66%

Answer 2

Hi friend,

Given,

Volume =4/3 πR³

∆V/V = 3 π∆r/r
=3×(0.1/5.3)

=0.05666666

∆V/V ×100 =5.6666

Percentage error =5.6℅.