the radius of a sphere is increased by 10%.percentage increase in volume
Answers
Answered by
87
let radius be r
volume =4/3(22/7×r^3)
radius =r+10%of r=r+(r/10)=11r/10
now new volume =4/3(22/7×1.1r×1.1r×1.1r)
now increase in volume =new volume -volume
percent increase in volume =(increase in volume×100)/original volume
volume =4/3(22/7×r^3)
radius =r+10%of r=r+(r/10)=11r/10
now new volume =4/3(22/7×1.1r×1.1r×1.1r)
now increase in volume =new volume -volume
percent increase in volume =(increase in volume×100)/original volume
Answered by
29
Answer:
Step-by-step explanation:
Let radius be r
Volume =4/3(22/7xr^3)
Radius =r+10%of r =r+(r/10)=11r/10
Now volume is =4/3(22/7x1.1rx1.1rx1.1r)
Now increase are in volume =new volume -volume
Percent increase in volume =(increase in volume x100)/original volume
If my answer is helpful to you please mark as a brainlist answer
Similar questions