Question

the radius of a sphere is increased by 10 percentage. prove that the volume will be increased by 33.1​

Answer 1

Step-by-step explanation:

Let the initial radius of the sphere be r and Volume be V.

$\therefore \: V= \frac{4}{3} \pi \: {r}^{3}$

When the radius of a sphere is increased by 10%. Let the new radius be $r_1$ and Volume be $V_1$

$r_1= r + 10\%\: of \: r\\</p><p>= r+0.1r\\</p><p>= 1.1r\\Now\\</p><p>V_1=\frac{4} {3}\pi\:r_1^3\\</p><p>=\frac{4} {3}\pi\:(1.1r)^3\\</p><p>=\frac{4} {3}\pi\:\times 1.331\:r^3\\</p><p>\therefore V_1=1.331\frac{4} {3}\pi\: r^3$

Increase in Volume

$=V_1 - V\\</p><p>=1.331\frac{4} {3}\pi\: r^3-\frac{4} {3}\pi\: r^3\\</p><p>=0.331\frac{4} {3}\pi\: r^3$

Answer 2

Answer:

here is ur answer!

plz look at above pic.

hope this will helps u.....