The radius of a sphere is increased by 10%. Prove that the volume will be increased by 33.1% approximately
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yes..................
RohanStuding12:
But how
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Let the radius of the sphere be r.
Therefore the volume of the sphere =
4/3πr*3...
Now the sphere is increased by 10%
=>new radius =10/100×r =>r/10.
Now new radius=r/10+r = 11r/10
New volume =4/3π(11r/10)*3
=4/3π1331r*3/1000
Increased volume =>4/3π1331r*3/1000-4/3πr*3
LCM =3000
Increased volume => 4/3π×331r*3/1000
Percentage of volume increased =>
4/3π331r*3/1000×100/(4/3πr*3)=>33.1%
Therefore the volume of the sphere =
4/3πr*3...
Now the sphere is increased by 10%
=>new radius =10/100×r =>r/10.
Now new radius=r/10+r = 11r/10
New volume =4/3π(11r/10)*3
=4/3π1331r*3/1000
Increased volume =>4/3π1331r*3/1000-4/3πr*3
LCM =3000
Increased volume => 4/3π×331r*3/1000
Percentage of volume increased =>
4/3π331r*3/1000×100/(4/3πr*3)=>33.1%
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