The radius of a sphere is increased by 10%, then
by what percent its surface area increases?
Answers
Answered by
0
Answer:
21% answer
Step-by-step explanation:
kud likhe lena
Answered by
0
Answer:
Let radius of sphere=r
Volume=
3
4
πr
3
Radius is increased by 10 %=r+
100
10
r
=r+
10
r
=
10
11r
Volume =
3
4
π×
1000
11
3
r
3
Increased volume %=
3
4
πr
3
(
1000
1331
−1)
3
4
πr
3
×100
=
1000
331
×100=33.1%
∴Volume increased by 33.1%
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