Math, asked by ansh1118, 9 months ago

The radius of a spherical balloon increase from 7cm to 14 cm as air is being pumped into it .find the ratio of the surface are of the balloon in the two case.​

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Answered by katakamsaiakshay192
4

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Answered by sourya1794
9

\bf{\underline{\red{Correct\:Question:-}}}

The radius of a spherical balloon increase from 7cm to 14 cm as air is being pumped into it .find the ratio of the surface are of the balloon in the two case.

\bf{\underline{\green{Solution:-}}}

\bf\boxed\star\pink{\underline{\underline{{For\:first\:case}}}}:-

\bf\:Given:-

  • \bf\:Radius=7\:cm

\bf\implies\:S.A=\:4π{r}^{2}

\bf\implies\:S.A=\:4\times\:\dfrac{22}{7}\times\:{(7)}^{2}

\bf\implies\:S.A=\:4\times\:\dfrac{22}{7}\times\:7\times\:7

\bf\implies\:S.A=\:4\times\:22\times\:7

\bf\implies\:S.A=\:616\:c{m}^{2}

\bf\boxed\star\blue{\underline{\underline{{For\: second\:case}}}}:-

\bf\:Given:-

  • \bf\:Radius=14\:cm

\bf\implies\:S.A=\:4π{r}^{2}

\bf\implies\:S.A=\:4\times\:\dfrac{22}{7}\times\:{(14)}^{2}

\bf\implies\:S.A=\:4\times\:\dfrac{22}{7}\times\:14\times\:14

\bf\implies\:S.A=\:4\times\:22\times\:2\times\:14

\bf\implies\:S.A=2464\:c{m}^{2}

Now, we have

\bf\purple{{In\:first\:case,}}

  • \bf\:S.A=616\:c{m}^{2}

\bf\orange{{In\: second\:case,}}

  • \bf\:S.A=2464\:c{m}^{2}

then,

\bf\:Ratio\:of\:S.A=\dfrac{616}{2464}

\bf\:Ratio\:of\:S.A=\dfrac{1}{4}

\bf\:Ratio\:of\:S.A=1:4

[Here, S.A indicates Surface area]

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