Physics, asked by vishal6263, 1 year ago

The radius of a thin wire is 0.16 mm . The area of cross section of the wire in mm with correct number of significant figures​

Answers

Answered by sujeewasandeepa
2

Answer:

0.080425mm^{2} just applied to the area=πr^{2}

Explanation:


vishal6263: plezz i want explanation
sujeewasandeepa: Okay I'll update the answer,
sujeewasandeepa: The equation we use to find the are of a circle is (pi)*(radius)^2 here the cross section of the wire is also circular, so we can substitute 0.16mm to the radius, and value of (pi) is 22/7 when we solve this equation we get the answer 0.080425mm^2.
Answered by handgunmaine
1

The area of cross section of the wire is 0.08\ mm^2.

Explanation:

It is given that,

The radius of a thin wire is 0.16 mm.

To find,

The area of cross section of the wire.

Solution,

The cross section is in the form of circle whose area is given by :

A=\pi r^2

Where \pi=\dfrac{22}{7}=3.14

A=\pi (0.16\ mm)^2

A=0.0804\ mm^2

In significant figures,

A=0.08\ mm^2

So, the area of cross section of the wire is 0.08\ mm^2.

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