Physics, asked by vishal6263, 11 months ago

the radius of a thin wire is 0.16 mm the area of cross section of the wire is mm square with correct number of significant figures​

Answers

Answered by tiwaavi
18

Answer ⇒ Area = 0.08 mm²

Explanation ⇒ Given,

Radius of the thin wire is 0.16 mm.

Thus, area of the cross section of the wire is 22/7 × r²

= 22/7 × 0.16 × 0.16

= 0.08045 mm².

Now, In significant figures, it should also have two digits after the decimal.

Thus, Area = 0.08 mm²

Hope it helps.

Answered by simraan62
5

Answer:

0.08

Explanation:

π×r^2

22/7×(0.16)^2

=0.08045mm^2

therefore significant figures is 2

=0.08

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