the radius of a thin wire is 0.16 mm the area of cross section of the wire is mm square with correct number of significant figures
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Answered by
18
Answer ⇒ Area = 0.08 mm²
Explanation ⇒ Given,
Radius of the thin wire is 0.16 mm.
Thus, area of the cross section of the wire is 22/7 × r²
= 22/7 × 0.16 × 0.16
= 0.08045 mm².
Now, In significant figures, it should also have two digits after the decimal.
Thus, Area = 0.08 mm²
Hope it helps.
Answered by
5
Answer:
0.08
Explanation:
π×r^2
22/7×(0.16)^2
=0.08045mm^2
therefore significant figures is 2
=0.08
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