Question

The radius of a water pipe decreases from 10 to 5 cm. If the average velocity in
the wider portion is 4 m/s, find the average velocity in the narrower region.

Answer 1

Answer:

In physics and engineering, in particular fluid dynamics, the volumetric flow rate is the volume of fluid which passes per unit time; usually it is represented by the symbol Q. The SI unit is cubic metres per second

Answer 2

Answer:

v = 16 m/s

Explanation:

Given,

The radius of a water pipe decreases from 10 to 5 cm.

The average velocity in the wider portion is 4 m/s.  (v1)

To find:The average velocity in the narrower region

Solution:

Applying continuity equation,

$A_1v_1 = A_2v_2\\\\v_2 = \dfrac{A_1v_1}{A_2} = \dfrac{\pi r_1^2v_1}{\pi r_2^2 } = \dfrac{10^2\times4}{5^2} = 16 \ m/s$