Physics, asked by saragadamsanath, 3 months ago


The radius of a well is 7m. Water in it is at a depth of 20m and depth of water column is 10m. Work done in pumping out water completely from the well is, (g = 10ms?)​

Answers

Answered by Anonymous
2

Answer:

hope this helped you dear friend

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Answered by paras4730
2

Total mass of water =m

m= density ×volume

=1000×πR2(h)

=1000×722×72×10

=1540000kg

By using center of mass concept ,center of mass of water is at depth of (20+5)h from the top.

Hence work done =mg(20+5)

=150000×10×25

=385000000J

=385000KJ

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