the radius of a wheel of a cycle is 70 cm final the distance covered by the cycle during the time in which the wheel makes 2000 resolution
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Given load =250gf, load arm =28cm,
effort arm = 7cm and effort =E.
Now, load × load arm = effort × effort arm
250×28=E×27
E=
7
250×28
=1000gf=1kgf or 10N
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Answer:
50 revolution = 88 m
1 revolution = 88/50 m = 1.76 m
now ,
2phi × radius = 1.76 m
radius = 0.28 m.
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