the radius of a wire is decreased to one third if volume remains the same the length will become
Imdad11:
what answer will be
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HEY DEAR ... ✌
______________________
original volume = πr²l
new radius is r/3 let new lwngth be L
new volume = π(r/3)² L
π(r/3)² L = πr²l
r²/9 L = r²l
1/9 L = l
L = 9 l
length will be 9 times the original length
HOPE , IT HELPS ... ✌
______________________
original volume = πr²l
new radius is r/3 let new lwngth be L
new volume = π(r/3)² L
π(r/3)² L = πr²l
r²/9 L = r²l
1/9 L = l
L = 9 l
length will be 9 times the original length
HOPE , IT HELPS ... ✌
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