Chemistry, asked by kunaranil7139, 1 year ago

The radius of ag+ ion is 126 pm while that of i– ion is 216 pm. the co-ordination number of ag in agi is

Answers

Answered by saraswathi6
22
radius ratio Rc/Ra=126/216=0.583 therefore Co.no=6 (0.414-0.742 co.no=6)
Answered by IlaMends
18

Answer:

The co-ordination number of Ag in AgI is 6.

Explanation:

Radius ratio \=\frac{\text{Radius of the cation}r_+}{\text{Radius of the anion}r_-}

Radius of Ag^+ ion = 126 pm

Radius of I^- ion = 216 pm.

Radius ratio = \frac{r_+}{r_-}=\frac{126 pm}{216 pm}=0.5833

The ratio comes in the range of 0.414 to 0.732 of octahedral structural arrangement which means the coordination number is 6.

The co-ordination number of Ag in AgI is 6.

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