Physics, asked by akyadavhpins090, 1 year ago

The radius of atom is of the order of 1 angaston and radius of nucleus is of the order of Fermi.How many magnitudes higher is the volume of atom as compared to the volume of nucleus?

Answers

Answered by Anonymous
40
Let radius of nucleus be 'r'
And radius of atom be 'R'
Their shape can be supposed to be sphere
Vol Ratio = Vol of atom / Vol of nucleus
= (4/3πR³)/(4/3πr³) = (R/r)³
Now , R=10^-10m
r= 10^-15m
Volume Ratio = (10^-10/10^-15)³ = 10^125
Hence , volume of atom is 10^125 times greater than volume of nucleus

QGP: Hello. (10^5)^3 = 10^15 and not 10^125
QGP: Please correct your answer
Anonymous: Ohh , Thanks
Anonymous: But I'm not able to edit it...
QGP: Try refreshing the page
Anonymous: Still sucking at that... Leave and thanks again
QGP: If you are still not able to edit it, then it's okay. No problem. You still have a good explanation
Anonymous: Ty buddy
QGP: Welcome
Answered by QGP
54
Radius of atom ≈ 1 Å = 1.0 × 10^(-10) m
Radius of nucleus ≈ 1 fermi = 1.0×10^(-15) m

So, ratio of radius of atom to radius of nucleus is:

1 Å/1 fermi = 10^(-10)/10^(-15) = 10^5


Now, volume = (4/3)πr³

So, ratio of volumes = (ratio of radii)³
So, ratio of volumes = (10^5)³ = 10^15


Thus, an atom has around 10^15 times more volume than a nucleus
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