Question

the radius of capillary is 2 x 10 -3 the a liquid of weight is 6.28 x 10 -4 and maybe remains in the capillary then what will be the surface tension of liquid​

Answer 1

Answer:

5 × 10^-2 Newton

sorry by mistake I write 2TL In place TL

I sent a pic

Explanation:

Thanks for Reading

Answer 2

Answer:

Explanation:

Given

radius of capillary $r=2\times 10^{-3}\ m$

Weight of Liquid$=6.28\times 10^{-4}\ N$

Weight will be balanced by surface tension

thus

$Tension\ Force=2\times TL$

$Tension=2\times T\times (2\pi r)$

$Weight=mg$

$2\times T\times (2\pi r)=mg$

$T=\frac{mg}{4\pi \cdot r}$

$T=\frac{6.28\times 10^{-4}}{4\pi \times 2\times 10^{-3}}$

$T=0.0249 N/m$