the radius of circle is 13 centimetre and the length of 1 its cold is 24 centimetre find distance of chord<br /> from the center
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Answer:
GIVEN: A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm
TO FIND : The perpendicular distance of the chord from O. Let it be called OM.
OM is perpendicular to the chord AB.
Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm
In right triangle AMO , Using Pythagoras’s Theorem,
AO² = AM² + OM²
=> 13² = 12² + OM²
=> 169 = 144 + OM²
=> OM² = 169 - 144 = 25
=> OM = √25 = 5 cm.
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