the radius of circle is 13 cm length of one of its side is 10 cm find the distance of chord from centre
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4
given
the radius is 13 cm
the length of its chord is 10cm
draw a triangle from the centre to the endings of the chord
draw a perpendicular bisector from the centre to chord
in one triangle hyp is 13 cm (radius)
and base is 5 cm =10/2
by phythougours theorem
13^2=x^2+5^2
169-25=x^2
x=12cm
therefore the distance between the centre and the chord is 12 cm
the radius is 13 cm
the length of its chord is 10cm
draw a triangle from the centre to the endings of the chord
draw a perpendicular bisector from the centre to chord
in one triangle hyp is 13 cm (radius)
and base is 5 cm =10/2
by phythougours theorem
13^2=x^2+5^2
169-25=x^2
x=12cm
therefore the distance between the centre and the chord is 12 cm
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2
1st draw a rough sketch for reference
use pythagorus theorem
you will get the answer as8.3 cm
use pythagorus theorem
you will get the answer as8.3 cm
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