Question

the radius of circle is 5cm the distance a chord from the centre is 4 cm find the length of chord​

Answer 1

Step-by-step explanation:

you have to use h^2=b^2+s^2

Answer 2

Answer:

ANSWER:

In the given circle, radius OA = 5 cm: distance of the chord AB from the centre is 4 cm.

So, segment AM = segment MB (Perpendicular drawn from the centre to a chord bisects the chord)

By using Pythagoras theorem, in right triangle AOM,

AM2 + OM2 = OA2

⇒ AM2 + 42 = 52

⇒ AM2 +16 = 25

⇒ AM2 = 25 – 16

⇒ AM2 = 9

⇒ AM = 3 cm

But segment AM = segment MB = 3 cm

∴ Segment AB = segment AM + segment MB = 3 cm + 3 cm = 6 cm

Therefore, the length of the chord is 6 cm.