Question

the radius of circle is greater than the radius of other circle is greater than 3m the same of these area is 89π m2 find the radius of each circle.

Answer 1

Step-by-step explanation:

radius of smaller circle = 5m

radius of larger circle = 8m

Step-by-step explanation:

Formula:-

Area of circle with radius r is given by,

Area of circle, A = πr²

Let 'r' be the radius of smaller circle, then radius of large circle = r+3

It is given that sum of areas = 89π m^2

To find r

Sum of  areas = πr² + π(r +3)² =  89π m^2

⇒ π[r² + (r +3)²] =  89π

⇒ r² + (r +3)² = 89

⇒ r²  + r² +  6r + 9 = 89

⇒ 2r² +  6r + 9 - 89 = 0

⇒ 2r² +  6r - 80 = 0

⇒ r² +  3r  - 40 = 0 ----(1)

eq(1) is a quadratic equation.

Solving we get

r = 5 and r = -8

we take +ve values, so r = 5

Therefore radius of smaller circle = 5m

And radius of larger circle = r + 3 = 5 = 3 = 8m

Answer 2

Answer:

ANSWER IS 8 M

Step-by-step explanation:

PLEASE~~~~~~ADD~~~~~AS~~~~~~~~BRAINLIST

Formula:-

Area of circle with radius r is given by,

Area of circle, A = πr²

Let 'r' be the radius of smaller circle, then radius of large circle = r+3

It is given that sum of areas = 89π m^2

To find r

Sum of areas = πr² + π(r +3)² = 89π m^2

⇒ π[r² + (r +3)²] = 89π

⇒ r² + (r +3)² = 89

⇒ r² + r² + 6r + 9 = 89

⇒ 2r² + 6r + 9 - 89 = 0

⇒ 2r² + 6r - 80 = 0

⇒ r² + 3r - 40 = 0 ----(1)

eq(1) is a quadratic equation.

Solving we get

r = 5 and r = -8

we take +ve values, so r = 5

Therefore radius of smaller circle = 5m

And radius of larger circle = r + 3 = 5 = 3 = 8m