Question

The radius of circular ends of a solid frustum of a cone are 33 cm and 27 cm. Its slant height is 10 cm. Find its total surface area of frustum.

Answer 1

Answer:

Total Surface area of frustum = 7,599.42 cm²

Step-by-step explanation:

SOLUTION :  

Given :  

Radius of top circular ends ,R = 33 cm

Radius of bottom circular end of bucket ,r = 27 cm

Slant height of a frustum , l  = 10 cm

Total Surface area of frustum = π(R+ r)l + πR² + πr²

= π(33 + 27) 10 + π × 33² + π × 27²

= π× 60 × 10 + π × 1089 + π × 729

= π(600 + 1089 + 729)

= 2418 π  

= 2418 × 22/7  

= 53196/7  

= 7,599.42 cm²

Hence, the Total Surface area of frustum = 7,599.42 cm²

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Answer 2

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7,599.42 cm²

Step-by-step explanation:

Given,

Radius of top circular ends ,R = 33 cm

and

Radius of bottom circular end of bucket ,r = 27 cm

also,

Slant height of a frustum , l  = 10 cm

now,

Total Surface area of frustum = π(R+ r)l + πR² + πr²

= π(33 + 27) 10 + π × 33² + π × 27²

= π× 60 × 10 + π × 1089 + π × 729

= π(600 + 1089 + 729)

= 2418 π  

= 2418 × 22/7  

= 53196/7  

= 7,599.42 cm²

Hence,

the Total Surface area of frustum = 7,599.42 cm²