Question

The radius of circular wire is 0.25m and the current is 5A the magnitude of magnetic field at the centre of the circular wire is

Answer 1

Answer:

12.57×10-⁶ T

Explanation:

EXPLANATION IS IN THE PHOTO

Answer 2

Question :

The radius of circular wire is 0.25m and the current is 5A , find the magnitude of magnetic field at the centre of the circular wire .

Answer :

The magnitude of magnetic field at the centre of the circular wire is 12.57 × 10^(-6) T.

Given :

Radius of the circular wire = 0.25m

Current = 5 A

To find :

Magnitude of magnetic field at the centre of the circular wire

Solution :

We know that ,

Magnetic field at the centre of a circular wire B = µo I / 2r

where µo is the magnetic permeability = 4π × 10^(-7) T m/A

Hence , B = (4π × 10^(-7) × 5 ) / (2 × 0.25)

B = (4π × 10^(-7) × 5 ) / 0.5

B = (4π × 10^(-7) × 5 × 10) / 5

B = (4π × 10^(-7) × 10)

B = (4π × 10^(-6) )

B = 12.57 × 10^(-6)

Hence, the magnitude of magnetic field at the centre of the circular wire is 12.57 × 10^(-6) T.

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