Question

The radius of cone is increased by 25% and height is decreased by 20%, then percentage change in volume is (a) 20% (b) 12.5% (c) 37.5 % (d) None of above




I will mark you brainlist what ever
please Answer it argent
​

Answer 1

Answer:

20 percent

Step-by-step explanation:

Hlo Everyone !

ᴘʟᴇᴀꜱᴇ ꜱᴜʙꜱᴄʀɪʙᴇ ᴍʏ ᴄʜᴀɴɴᴇʟ:

" Anu and Nanu creations"

ɪ ʜᴏᴘᴇ ʏᴏᴜ ᴀʟʟ ᴡɪʟʟ ꜱᴜᴘᴘᴏʀᴛ ᴍᴇ.

please

you can send screenshot of my channel subscribed so I can be your follower

Answer 2

None of these ☑️

Original volume of a cone = [\piπ r²h]÷3

Given that,

Radius is increased by 25%

Height is decreased by 20%

New Volume = \piπ ×[r25/100)×r}]²×[h-(20/100)×h

= \piπ ×(5r/4)²×(4h/5)

= \piπ ×(25r²/16)×(4h/5)

= \piπ ×5r²/4×h

= [5\piπ r²h]÷4

Change in Volume = [(5\piπ r²h)÷4] - [(\piπ r²h)÷3]

= [15\piπ r²h - 4\piπ r²h]÷12

= [11\piπ r²h]÷12

Percentage change = [(11\piπ r²h/12)÷(\piπ r²h/3)]×100

= 275% INCREASE

[ Kinda Mark as Brainliest ]

$\huge{♡}{\underline{\mathtt{\pink{|}\orange{|}{\red{A}\pink{n}\green{g}\blue{e}\pink{l}\purple{i}\orange{c}\red{-}\pink{B}\green{a}\blue{e}\purple{|}\pink{|}}}}}{♡}$