The radius of curvature at the point (S,Y ) on the
curve 5=c log sec y is
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The radius of curvature is c tanψ
Step-by-step explanation:
Given,
s = c log(secψ)
Now, differentiating with respect to ψ, we get
ds/dψ = d/dψ {c log(secψ)}
= c d/dψ {log(secψ)}
= c * 1/secψ * d/dψ (secψ)
= c * 1/secψ * secψ tanψ
= c tanψ
Therefore the radius of curvature is
ρ = ds/dψ = c tanψ .
Problem:
1. Find the radius of curvature at the point (s, ψ) of the curve s = a secψ tanψ + a log(secψ + tanψ).
2. Find the radius of curvature of y = x e⁻ˣ at a point where y is maximum.
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