Question

The radius of curvature of a concave mirror is 20cm . Where should an object be placed in front of concave mirror so that real image of double the size of the object is formed?

Answer 1

Answer:

Explanation:

We know that from mirror formula

1/f=1/v+1/u

1/-10=1/v+1/u

It is given that

Height of image/Height of object=1/2

Hence

-v/u=1/2

v=-2u

-1/10cm=-1/2u+1/u

-1/10cm=1/u

u=-10cm

Hope it helps

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