Question

the radius of curvature of a converging mirror is 30cm at what distance from the mirror should an object be placed so as to obtain a virtual image​

Answer 1

Answer:

Given,

Focal length, f=−30 cm if u=−x

real ⇒ same side ⇒v=−ve

Magnification, m=

u

v

⇒v=m×u=3×(−x)=−3x

From mirror formula,

f

1

=

v

1

+

u

1

We get

−30

1

=

−3x

1

+

−x

1

⇒

30

1

=

3x

1+3

⇒

4

3x

=3⇒x=40 cm

So object should be placed at 40 cm to the mirror.

Explanation:

please mark brainlist answer

Answer 2

The question is:

The radius of curvature of a converging mirror is 30 cm. At what distance from the mirror should an object be placed so as to obtain a virtual image?  

(a) infinity  

(b) 30 cm  

(c) Between 16 cm and 30 cm  

(d) Between 0 cm and 15 cm

The correct option is d, i.e., Between 0 cm and 15 cm.

Given:

radius of curvature of a converging mirror= R= 30 cm

object nature= virtual

To find:

The distance between mirror and the object.

Solution:

• Concave mirrors are a type of spherical mirror which is curved inwards.
• Concave mirror is also known as converging mirror as it has the tendency to converge the light rays to a point called focus.

As we know that,

R= f/2

f= 30/2

f=15 cm

• As per option a, if we will place the object at infinity then the image formed will be real and inverted.
• As per option b, if we will place the object at 30 cm that is at the radius of curvature then the image formed will be real and inverted.
• As per option c, if we will place the object between 16 cm and 30 cm that is between radius of curvature and focal length then the image formed will be real and inverted.
• As per option d, if we will keep the object between 0 cm and 15 cm that is between the pole and the focal length then the image formed will be virtual and erect.

Therefore, the correct option is d, i.e., between 0 cm and 15 cm.

#SPJ2