Question

The radius of curvature of a convex lens are 0.04m and 0.0 refractive index is 1.5 its focal length is

Answer 1

Explanation:

The radius of curvature of a convex lens are 0.04m and 0.0 refractive index is 1.5 its focal length is Get the answers you ...breanly app

Answer 2

The focal length is 0.04 m.

Explanation:

Given that,

Radius of curvature = 0.04 m

Refractive index = 1.5

We need to calculate the focal length

Using formula of lens

$\dfrac{1}{f}=(\mu_{lens}-1)(\dfrac{1}{R_{1}}-\dfrac{1}{R_{2}})$

Put the value into the formula

$\dfrac{1}{f}=(1.5-1)(\dfrac{1}{0.04}-\dfrac{1}{-0.04})$

$\dfrac{1}{f}=0.5\times(\dfrac{2}{0.04})$

$f=\dfrac{0.04}{2\times0.5}$

$f=0.04\ m$

Hence, The focal length is 0.04 m.

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Topic : focal length

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