the radius of curvature of a convex mirror used as a rear view mirror in a moving car is '20' m a truck is coming from behind it at a distance of 3.5 metre calculate the a)position b)size of the image relative to the size of truck what will be the nature of the image.
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R = 2 m
f = R/2 = 1 m
u = -3.5 m
We know that
(a) 1/v + 1u = 1/f
⇒ 1/v + 1/(-35) = 1/1
⇒ 1/v = 1 + 1/3.5 = 1 + 10/35 = 1 + 2/7 = 9/7
∴ v = 7/9 = 0.77 m
So, the image is formed 0.77 m behind the mirror.
(b) Now, m = - (v/u) = - (0.77/ (-3.5) = (7/9)/3.5 = 1/4.5
As m is positive, so image formed is virtual and erect.
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