Question

The radius of curvature of a convex mirror used for rear view on a car is 4.00m. If the location of the bus is 6 meter from this mirror, Find the position of the image formed

Answer 1

Answer:

Given, radius of curvature, R = 3m

Object distance, u = - 5 m

Image distance, v = ?

Height of the image, hi, = ?

mark me

Answer 2

Answer:

The image is formed 1.5 m at the back of the mirror.

Explanation:

Given,

radius of curvature (R) = 4 m

object distance(u) = -6 m

Image distance = v

We know that,focal length ,f = $\frac{R}{2}$ = $\frac{4}{2}$ = +2 m

Since,  $\frac{1}{v} + \frac{1}{u } = \frac{1}{f}$

         $or, \frac{1}{v} = \frac{1}{f} - \frac{1}{u}$  

                   $= \frac{1}{2} - \frac{1}{(-6)}$

                    $= \frac{2}{3}$

  ∴ $v = \frac{3}{2}$  meter = 1.5 m

Thus,the image is formed 1.5 m at the back of the mirror.

Magnification(m) = $-\frac{v}{u}$ = + 0.25 m

So,the image is virtual ,erect and smaller in size.