Question

the radius of curvature of a convex mirror used on a moving automobile is 2.0 metre metre tractors coming behind it at a constant distance of 3.5 metre calculate the first position and the second the size of image related to the size of truck what will be the nature of the image​

Answer 1

Explanation:

R= 2cm

f = R/2 = 1cm

= u= -3.5m

we know that

1/f= 1/v+1/u

1/v+ 1/ -3.5 =1/1

1/v =1+ 1/3.5

1+10/35

= 1+2/7

= 9/7

v= 7/9 = 0.77m

so , the image formed 0.77m behind the mirror

2.m=-v/u

0.77/ - 3.5 = 7/9 /3.5

= 1/ 4.5

As m is positive, so the image is formed virtual and erect

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I hope it will help you