Physics, asked by carlwilkinson2009, 1 year ago

the radius of curvature of a convex mirror used on a moving automobile is 2.0m. A truck is coming behind it at a constant distance of 3.5m. Calculate the position and the size of image relative to the size of the truck .What will be the nature of the image?

Answers

Answered by Arushisin
403
f = r÷2 = 2m ÷ 2 = 1 m
u = -3.5 m
Using mirror formula,
1 ÷ -3.5 m + 1 ÷ v = 1 ÷ 1 m
1 ÷ v = 1 m + 1 ÷ 3.5 m
1 ÷ v = (3.5 + 1) m ÷ 3.5
1 ÷ v = 4.5 m ÷ 3.5
1 ÷ v = 9 ÷ 7 m
v = 7 ÷ 9 m
v = 0.78 m

Image will be virtual, erect and smaller than object.

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Answered by Sanav1106
0

The distance of the image is 0.7m and the magnification is 0.2.

Given,

A convex mirror whose radius of curvature is 2m. A truck is at a distance of 3.5m.

To find,

Position, size of image relative to the size of object and the nature of the image.

Solution,

As the truck is at a constant distance, we will assume them to be stationary because no change is there in the object's distance or height.

The object distance(u)=-3.5m

We know, R=2f

where R is the Radius of curvature and f is the focal length.

2=2f

f=1 m.

Let the image distance be v m.

According to the mirror formula,

1/v+1/u=1/f.

1/v=1/f-1/u

1/v=1-1/(-3.5)

=1+1/3.5

=4.5/3.5

=45/35

v=35/45.

=0.7m.

The size of the image relative to the size of the object is the Magnification and it can also be found out by image and object distance.

magnification= -v/u

=-0.7/-3.5

=0.2

The distance of the image is 0.7m and the magnification is 0.2.

Nature, The nature of the image will be virtual and erect.

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