Question

The radius of curvature of a railway line at a place is 0-8 km.
A train is running at 20 ms-1. The distance between the
two rails is 1-5 m. Find the elevation of the outer rail over
the inner one, so that the train may be able to run safely.​

Answer 1

Explanation:

Here is the answer 100×1.5÷100×9.8 = 1.5/98

Answer 2

Answer:

Explanation:

tan theta= v^2/(r*g) = 20^2/(800*10)

tan theta = 400/8000 = 1/20

slope = 1:20

the outer rail is 20 times higher than inner rail.