Question

The radius of curvature of concave mirror is 24 cm.object is placed at twice of focal length before mirror then find magnification​

Answer 1

Answer:

in this case the magnification is 1

Answer 2

Answer:

1

Explanation:

We are given that

Radius of curvature=24 cm

Focal length =$\frac{24}{2}=12 cm$

Focal length of concave mirror =-12 cm

Object distance=u=-2(12)=-24 cm

We have to find the magnification of concave mirror

Mirror formula :

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

Substitute the values then we get

$\frac{1}{-12}=\frac{1}{v}-\frac{1}{24}$

$\frac{1}{v}=\frac{-1}{12}+\frac{1}{24}=-\frac{1}{24}$

$v=-24 cm$

Magnification=$\frac{v}{u}$

Magnification=$\frac{-24}{-24}=1$

Hence, the magnification=1