Question

the radius of curvature of y=e× at x=0​

Answer 1

Answer:

Answer. The radius or curvature to be r =2√2 ,it would be interesting to find where the centre of curvature of that circle is . r = √[(- 2 -0)^2 +(3 - 1)^2] = √8 = 2 √ 2 = radius of curvature.

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