the radius of curvaturer of concave mirror is 40centimeter. find position of an object in front of mirror, so that its real image is 2 times the size of object.
plz answer with solution please
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Answer: I have tried to answer. I hope this will help you..
If there is any doubt in mind you can tell..
Explanation:
Given that, radius of curvature ,R = -40 cm so focal length= -20 cm
Let the height of the object be h cm
According to the question, height of image should be -2h cm
we know that,
m= - v/u = -2h/h
v/u = 2
v = 2u
Mirror Formula
1/f = 1/u +1/v
- 1/20= 1/u +1/2u
-1/20 = 2+1 /2u
-1/20= 3/2u
-2u = 60
u = -30 cm
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