Question

the radius of each cirlce in the image is 6cm what is the area in (cm^2) of the quadrilateral formed by joining the centre's of the cirlce​​

Answer 1

Answer:

Let O be the center of a circle whose radius OA = 6 cm.

Its area = πr2=π(6)2=36πcm2

Now, the area of this circle is trisected by two

concentric circles having radii OB and OC respectively. 

∴ Area of the smallest circle ( with radius OC)

=336πcm2

⇒π×OC2=12π⇒OC2=12

⇒OC=23cm

Answer 2

Step-by-step explanation:

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