Question

The radius of earth is 6.37x10^6m. its mean density is 5.5x10^3kg/m3 and G is 6.66x10^-11Nm^2/kg^2. ^ Determine the gravitation potential on the surface of earth.

Answer 1

Answer:

gravitational potential, v= - GM/r

Explanation:

As density = mass/ volume

mass = volume× density

M = 4/3 π r^3 × density

Answer 2

Explanation:

Given that,

Radius of Earth, $r=6.37\times 10^6\ m$

Density, $d=5.5\times 10^3\ kg/m^3$

The gravitational potential is given by :

$V=\dfrac{-GM}{r}$

M is the mass of earth

M can be find by using the density formula as :

$d=\dfrac{M}{V}$

$M=d\times V$

$M=d\times \dfrac{4}{3}\pi r^3$

$M=5.5\times 10^3\times \dfrac{4}{3}\pi (6.37\times 10^6)^3$

$M=5.95\times 10^{24}\ kg$

$V=\dfrac{-6.66\times 10^{-11}\times 5.95\times 10^{24}}{6.37\times 10^6}$

V= -62208791.20 V

Hence, this is the require solution.