Question

the radius of earth is 6380km.a)how far does a point on equator travel in 24 hours b)find the speed of a point on the equator in m/s​

Answer 1

Answer:

a) 40086.72km b) 463.96 m/s

Step-by-step explanation:

radius of earth = 6380 km

point on equator travels, 2πr distance.

= 2×π×6380

= 40086.72km

speed of point = distance / time

= 40086.72 / 24

= 1670.28 km/hr

= 463.96 m/s

Answer 2

Answer:

The point travels 40086.72 km on equator in 24 hrs.

And required speed is 463.96 m/s.

Step-by-step explanation:

Given, radius of earth = r = 6380 km

we know,

Any point on equator travels total perimeter of the earth.

$perimeter \: = 2 \times \pi \times r$

$= 2 \times \pi \times 6380 = 2 \times \frac{22}{7} \times 6380 = \frac{2 \times 22 \times 6380}{7} = 40086.72 \: km$

Again,

$speed = \frac{distance}{time}$

$= \frac{40086.72}{24} = 1670.28 \: km. {hr}^{ - 1} = 1670.28 \times \frac{5}{18} m. {s}^{ - 1} = 463.96 \: m. {s}^{ - 1}$

The point travels 40086.72 km on equator in 24 hrs.

And required speed is 463.96 m/s.