The radius of earth is about 6400 km and that the mass is 3200 km and the mass of the earth is 10 times of mass of mass and object with mm and on the surface of Earth then its weight on surface of Mars will be
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The acceleration due to gravity at a distance r from the center of the Earth is given by:
g = GM/r^2 (eq.1)
… where G is the gravitational constant, and M is the mas of the Earth.
At the surface of the Earth, r = R (R = radius of the Earth) and g = 9.8m/s/s. Putting this into the equation gives you:
9.8 = GM/R^2 (eq.2)
When the height above the Earth is equal to the radius of the Earth, then r = 2R. Putting that into the equation gives:
g = GM/(4R^2) (eq.3)
Substitute euqation 2 into equation 3 and solve.
g = GM/r^2 (eq.1)
… where G is the gravitational constant, and M is the mas of the Earth.
At the surface of the Earth, r = R (R = radius of the Earth) and g = 9.8m/s/s. Putting this into the equation gives you:
9.8 = GM/R^2 (eq.2)
When the height above the Earth is equal to the radius of the Earth, then r = 2R. Putting that into the equation gives:
g = GM/(4R^2) (eq.3)
Substitute euqation 2 into equation 3 and solve.
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