Physics, asked by aryandhawan2802228, 1 month ago

The radius of Earth is R. At what distance above Earth's surface will the acceleration of gravity be 4.9 m/s2 ?

Answers

Answered by mayurikhatri
2

Answer:

Answer

Acceleration due to gravity at height h is given by

g

h

=

(R+h)

2

GM

we know g=GM/R

2

=9.8m/s

2

so GM/2R

2

=4.9m/s

2

putting in g

h

=

(R+h)

2

GM

2R

2

GM

=

(R+h)

2

GM

⟹R+h=

2

R

h=0.414R, where R is the radius of earth.

Answered by Anonymous
1

Answer:

Acceleration due to gravity at height h is given by

g

h

=

(R+h)

2

GM

we know g=GM/R

2

=9.8m/s

2

so GM/2R

2

=4.9m/s

2

putting in g

h

=

(R+h)

2

GM

2R

2

GM

=

(R+h)

2

GM

⟹R+h=

2

R

h=0.414R, where R is the radius of earth.

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