The radius of Earth is R. At what distance above Earth's surface will the acceleration of gravity be 4.9 m/s2 ?
Answers
Answered by
2
Answer:
Answer
Acceleration due to gravity at height h is given by
g
h
=
(R+h)
2
GM
we know g=GM/R
2
=9.8m/s
2
so GM/2R
2
=4.9m/s
2
putting in g
h
=
(R+h)
2
GM
2R
2
GM
=
(R+h)
2
GM
⟹R+h=
2
R
h=0.414R, where R is the radius of earth.
Answered by
1
Answer:
Acceleration due to gravity at height h is given by
g
h
=
(R+h)
2
GM
we know g=GM/R
2
=9.8m/s
2
so GM/2R
2
=4.9m/s
2
putting in g
h
=
(R+h)
2
GM
2R
2
GM
=
(R+h)
2
GM
⟹R+h=
2
R
h=0.414R, where R is the radius of earth.
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